# Monitor Your Website Automatically From Cron

I modified the title of my Blog the other day and it reminded me of a little
trick I have been using to monitor my website. I received an email alert stating
that my website was returning unexpected content. To do this, I created a really
basic cron job like this:

```bash
MAILTO=webmaster@example.com
3 * * * * if [[ `wget -q -O - https://www.grepular.com/|grep "Mike Cardwell | Blog"` == "" ]]; then echo "Website response unexepected"; fi
```

Once an hour it takes a look at https://www.grepular.com/ and if it doesn’t
receive a page that contains "Mike Cardwell | Blog" then it warns me that my
website is returning unexpected content and that I should take a look at it.
It's so simple that it can be done entirely inside cron without having to write
an external script to do the check.